Kamstrup MULTICAL 403 - Page 84

MULTICAL® 403
84
Kamstrup A/S · Technical description · FILE100000166_B_EN-55121689_M1_07.2023
Calculation
Condition
Heat energy
(E1, A1, A2)
Inlet
E1
= m
3
x
(t1-t2)k
t1
A1
= m
3
x(t5-t2)k
t1
A2
= m
3
x(t2-t5)k
t1
t1 > t2
If t1 = t2 then E1, A1, A2 = 0
If t5-t2 ≤ 0 then A1 = 0
If t2-t5 ≤ 0 then A2 = 0
θ
t1
> θ
hc
(meter type 6)
Outlet
E1= m
3
x
(t1- t2)k
t2
A1
= m
3
x(t5-t2)k
t2
A2
= m
3
x(t2-t5)k
t2
t1 > t2
If t1 = t2 then E1, A1, A2 = 0
If t5-t2 ≤ 0 then A1 = 0
If t2-t5 ≤ 0 then A2 = 0
θ
t1
> θ
hc
(meter type 6)
Cooling energy
(E3)
Inlet
E3
= m
3
x
(t2- t1)k
t1
t1 < t2
θ
t1
< θ
hc
(meter type 6)
Outlet
E3
= m
3
x
(t2 – t1)k
t2
t1 < t2
θ
t1
< θ
hc
(meter type 6)
Inlet/outlet energy
(E8, E9)
E8
= m
3
x
t1
E9 = m
3
xt2