Chapter 3: Output 3-11
Youwould followingcommand
:
breakd ownbelow:
K
9, 9999 = all lengths
h = “A”
9 = all
43 start character match for Code 93, 43h = “C”
FF termina
s,youwould
,suffixes,orformatted
racters uusethepreviousexample,but
a<C the
ing
342FF69001243FF
break isshownbelow:
LK
setupthesequenceeditorwiththe
line
SEQBLK62999941FF6A999942FF69999943FF
The ownofthecommandlineissh
SEQBL
sequenceeditorstartcommand
62 code identifier for Code 39
9999 code length that must match for Code 3
41 start character match for Code 39, 41
FF
6A
termination string for first code
code identifier for Code 128
9999 code length that must match for Code 128, 999
lengths
42 start character match for Code 128, 42h = “B”
FF termination string for second code
69 code identifier for Code 93
9999 code length that must match for Code 93, 9999 = all
lengths
tion string for third code
Toprogramthepreviousexampleusingspecificlength
havetocountanyprogrammedprefixes
cha aspartofthelength.Ifyo
assume
follow
R>suffixandspecificcodelengths,youwoulduse
commandline:
SEQBLK62001241FF6A001
The downofthecommandline
SEQB sequence editor start command