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Calculation of the results
c = nominal concentration of the standard acid solution
f = correction factor of standard acid solution (titer)
1) %N=
2) %Protein=
3) %NH
3
=
4) %NH
4
+
=
5) mg NH
4
+
= c x f (Consumption [ml] - Blank value [ml]) x 18,039
6) mg NH
3
+
= c x f (Consumption [ml] - Blank value [ml]) x 17,031
7) %NO
3
-
=
8) mg NO
3
-
= 62,005 x c x f (Consumption [ml] - Blank Value [ml])
9) mg N/l =
10) g N/l =
11) mg NH
3
/l =
12) g NH
3
/l =
13) mg NH
4
+
/l =
14) g NH
4
+
/l =
15) mg NO
3
-
/l =
16) g NO
3
-
/l =
1,4007 x c x f (Consumption [ml] - Blank value [ml])
Content [g]
Protein factor x 1,4007 x c x f (Consumption [ml] - Blank value [ml])
Content [g]
1,7031 x c x f (Consumption [ml] - Blank value [ml])
Content [g]
1,8039 x c x f (Consumption [ml] - Blank value [ml])
Content [g]
14007 x c x f (Consumption [ml] - Blank value [ml])
Volume [ml]
14,007 x c x f (Consumption [ml] - Blank value [ml])
Volume [ml]
17031 x c x f (Consumption [ml] - Blank value [ml])
Volume [ml]
17,031 x c x f (Consumption [ml] - Blank value [ml])
Volume [ml]
18039 x c x f (Consumption [ml] - Blank value [ml])
Volume [g]
18,039 x c x f (Consumption [ml] - Blank value [ml])
Volume [ml]
62005 x c x f (Consumption [ml] - Blank value [ml])
Volume [ml]
62,005 x c x f (Consumption [ml] - Blank value [ml])
Volumen [ml]
6,2005 x c x f (Consumption [ml] - Blank value [ml])
Content [g]