BK Precision 894 - Page 94

94
Ka= 0.00053995862
Ka =
msm fVZ
100
)
200
1)(
101
(
3



Ka is chosen because impedance is less than 500 Ohms.
Zm= Impedance of the DUT = 159.069 Ohms
fm= 100 KHz (test frequency)
Vs= 1 (voltage test signal)
Ka = 󰇛



) (1+200/1)(

󰇛


󰇜
Ka = 0.00003995862, but since we are using a 1 meter long testing
fixture, Ka needs to be compensated. (table 15)
Ka (new)= 0.00003995862+0.0005=0.00053995862
Kb= N/A
Kc= 0
Test frequency 100 KHz = Direct Calibrated Frequency= 0
See Table 16 and Table 17.
Kd= 0
L=1 meter, test cable lenght
Kd= 0.15%×(f
m
/ 1MHz)
2
× L
2
f
m
: test frequency [MHz]
Kd= 0.0015x(100,000/1,000,000)x(1)
2
Kd= 0.00015
Ke= 1
Room temperature during test= 20
o
. Temperature Factor =1.
See Table 18.
K
f
= 0
Fixture no available for this unit.
A
e
= ± [A
L
× A+(K
a
+K
b
+K
c
)×100+ K
d
+ K
f
]×K
e
[%]



󰇟󰇛

󰇜

󰇛
  
󰇜
  
󰇠

=  0.168995862%=0.00168995862
Finding the valid range: 0.168995862%x10.0061nF = 1.69098949E-11
10.0061nF + 1.69098949E-11= 10.02301nF
10.0061nF - 1.69098949E-11= 9.9891 nF
Valid range of measurements= [10.02301 nF, 9.9891 nF]
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