Siemens SIMOTICS T-1FW6 - Page 115

Configuration
5.3 Examples
1FW6 Built-in torque motors
Configuration Manual, 07/2017, 6SN1197-0AE00-0BP9
113
The following applies for the required acceleration torque:
M
a
= (J + J
m
) • α
Since the moment of inertia J
m
for the 1FW6 motor is not known at the time of configuring,
then initially J
m
= 0 kgm
2
must be assumed.
M
a
= 5.1 kgm
2
• 52.36 rad/s
2
= 267 Nm
To accelerate the specified mass, a torque M
a
of 267 Nm is required.
M
m
= M
r
+ M
a
M
m
= 100 Nm + 267 Nm = 367 Nm
Together with the constant frictional torque M
r
, a motor torque of M
m
= 367 Nm. is obtained.
A suitable motor can be selected from the "Built-in torque motors: overview" table in
accordance with the following criteria:
Maximum torque at least 367 Nm.
Maximum speed (specifying the max. torque): at least 100 rpm.
Suitable motors are:
1FW6090-0PB15-2JC2 (diameter 230 mm, length 190 mm)
1FW6130-0PB05-1JC2 (diameter 310 mm, length 90 mm)
The moment of inertia of the motor 1FW6090-0PB15-2JC2 is J = 0.0465 kgm
2
.
The accelerating torque M
a
can now be corrected to:
M
a
= (5.1 kgm
2
+ 0.0465 kgm
2
) • 52.36 rad/s
2
= 269 Nm
This means that the total motor torque required increases M
m
= M
r
+ M
a
up to 369 Nm.
The moment of inertia of the motor 1FW6130-0PB05-1JC2 is J = 0.0637 kgm
2
.
The accelerating torque M
a
can now be corrected to:
M
a
= (5.1 kgm
2
+ 0.0637 kgm
2
) • 52.36 rad/s
2
= 270 Nm
This means that the total motor torque required increases M
m
= M
r
+ M
a
up to 370 Nm.