ABB ACH580-31 - Fuses (IEC)

Example 1: P
n
for -206A-4 is 110 kW. The supply voltage ( U ) is 350 V. The motor
nominal voltage is 400 V.
Calculate the ratio between the supply voltage and required output voltage as
follows: U / U
n
= 350 V / 400 V = 0.875. From the graph we can see that P / P
n
= 0.975.
The derated power P = 0.975 × 110 kW = 107 kW.
To boost the output voltage to correspond the nominal supply voltage 400 V,
increase the DC voltage to 400 V × √2 = 567 V.
Example 2: P
n
for -096A-4 is 75 hp. The supply voltage ( U ) is 450 V.
U / U
n
= 450 V / 480 V = 0.938. From the graph we can see that P / P
n
= 1.00.
The derated power P = 1.00 × 75 hp = 75 hp.
To boost the output voltage to correspond the nominal supply voltage 480 V,
increase the DC voltage to 480 V × √2 = 679V.
Fuses (IEC)
Fuses protect the input cable in short-circuit situations. They also restrict drive
damage and prevent damage to adjoining equipment in case of a short-circuit
inside the drive. ABB recommends the high speed aR fuses specified below. The
gG fuses can be used for frame R3 if they operate rapidly enough (max. 0.1 seconds).
The operating time depends on the supply network impedance and the
cross-sectional area and length of the supply cable. Obey the local regulations.
Note: Fuses from other manufacturers can be used if they meet the ratings and
the melting curve of the fuse does not exceed the melting curve of the fuse
mentioned in the table.
178 Technical data