Operation
46
F-FEM-CON — User’s Guide
Solution:
1. The necessary gain:
Choosen G = 800.
2. The error on account of the load cell:
is related to the rated torque value of the dyno.
(Factor 1000 / 400 stands for the ratio M
DLC
/ M
DD
)
The error on account of the F-FEM-CON:
is related to the rated torque value of the dyno.
Factor 5/4 stands for the ratio: Measuring range of DMS input for G = 800
with 5 mV to maximum input fullscale level with
Added-up errors as geometrical sum of both
This is equivalent to 0.3 Nm.
Example
For Gain = 200 and indicated value of 400 (half fullscale) is the Raw value
equivalent to 10 mV (= 400 * 1000 / (200 * 200)).
Example
Dyno with 400 Nm rated torque value (M
DD
) and a load cell of 1000 Nm
converted rated torque value (M
DLC
= Force * Lever arm),
sensitivity of s
LC
= 2 mV/V and total errors of 0.03 % related to rated force value
(within a temperature window of 10 °C).
Required:
1. Determine gain value
2. Which maximum error is to expect for 25 °C +
5 °C by thermal steady state
(regardless of other mechanical effects like hysteresis, ...)?
G
800
s
LC
---------
M
DLC
M
DD
---------------
×
800
2
---------
1000
400
------------
× 1000==≤
0.03 %
1000
400
------------
× 0.075 %=
2mV V 5V
400Nm
1000Nm
---------------------
××⁄ 4 mV=
0.075
2
0.00625
2
+ 0.0753 %=