Chapter 10 Appendix
353
2) Calculation of Continuous Operation Thrust
Figure out the continuous operation thrust F
t by following the formula.
First, check the operation pattern of t
1a/t1d/t2a/t2d to find out that
Arrival speed (Vmax) =
0.05 × 0.098 → 0.07m/s and,
therefore it is greater than the set speed 62mm/s (0.06m/s), thus the pattern is the trapezoid
type.
Therefore, t
1a/t1d/t2a/t2d = 0.062/0.098 → 0.63s.
Secondary, if calculating t
1f/t2f;
Rated speed movement distance = 0.05 – {(0.062 × 0.062) / (2 × 0.098)} × 2 → 0.011m, thus
t
1f/t2f = 0.011 / 0.062 → 0.17s
Also, if calculating F
1a/F1f/F1d/F2a/F2f/F2d from the formula;
F
1a = F2d = (9 + 100) × 9.8 – (9 + 100) × 0.098 → 1058N
F
1d = F2a = (9 + 100) × 9.8 + (9 + 100) × 0.098 → 1079N
F
1f = F2f = fw = (9 + 100) × 9.8 → 1068N
If substituting the values above to the continuous operation thrust formula;
Ft =
F1a
2
× t1a + F1f
2
× t1f + F1d
2
× t1d + F0
2
× t0 + F2a
2
× t2a + F2f
2
× t2f + F2d
2
× t2d + Fw
2
× tw
t
=
{(1058 × 1058) × 0.63 + (1068×1068) × 0.17 + (1079 × 1079) × 0.63 + (19600 × 19600) ×
3 + (1079 × 1079) × 0.63 + (1068 × 1068) × 0.17 + (1058 × 1058) × 0.63 + (1068 × 1068) × 2}
/ (0.63 + 0.17 + 0.63 + 3 + 0.63 + 0.17 + 0.63 + 2) → 12113N
Since the answer exceeds 10200N, which is the rated thrust of Ultra-High Thrust Actuator 2
tone type, the operation is not allowed with this operation pattern.
Now, try to extend the standby time (to lower the duty).
In this case, F
t = 9814N assuming tw = 6.12s (t = 12s), thus the operation is available.
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