Configuration   
5.3 Examples 
  1FN3 linear motors 
128  Configuration Manual, 10/2018, 6SN1197-0AB86-0BP2 
Peak load motor 
1FN3150-4WC00-0BA1 
F
1
 = m
ges 
· a + F
r 
= 2617 N 
F
2
 = F
r
 = 100 N 
F
3
 = -m
ges
 · a + F
r
 = - 2417 N 
F
4
 = 0 N 
F
5
 = -m
ges
 · a - F
r
 = - 2617 N 
F
6
 = F
4
 - F
r
 = - 100 N 
F
7
 = m
ges
 · a - F
r
 = 2417 N 
 F
eff
 = 1246 N 
The effective force therefore remains 
below the permissible value of F
N
 = 
Travel to position s
MAX
 
 
 
Dwell time 
Travel to position s
0
 
Continuous load motor 
1FN3150-4NB80-0BA1 
F
1
 = m
ges 
· a + F
r 
= 2777 N 
F
2
 = F
r
 = 100 N 
F
3
 = -m
ges
 · a + F
r
 = - 2577 N 
F
4
 = 0 N 
F
5
 = -m
ges
 · a - F
r
 = - 2777 N 
F
6
 = F
4
 - F
r
 = - 100 N 
F
7
 = m
ges
 · a - F
r
 = 2577 N 
 F
eff
 = 1325 N 
The effective force therefore remains 
below the permissible value of F
N
 
Travel to position s
MAX
 
 
 
Dwell time 
Travel to position s
0
 
Final selection of the primary section  
For the example considered here, for a peak load motor, primary section 1FN3150-4WC00-
0BA1 is suitable, and for a continuous load motors, primary section 1FN3150-4NB80-0BA1. 
Which primary section is best suited to the specified duty cycle can be derived from the 
following summary: 
 
Values from the data sheet 
Values from the duty cycle 
Decision-making criteria for the primary section include: 
●  Size and installation conditions 
●  Thermal conditions 
●  Idle times 
●  Power reserves for peak and continuous loads 
●  Acceleration and velocity class 
●  Velocity class 
●  Converter power module