Panasonic MINAS A6 Series - Page 272

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Default: [ ]
1. Details of parameter
[Class 6] Special setting
Pr6.11
Current response setup
Range Unit Default
Related
control mode
10 to 100 % 100 P S T F
Finetunethecurrentresponsewithrespecttodefaultsetup(100%).
Pr6.13
2nd Inertia ratio
Range Unit Default
Related
control mode
0 to 10000 % 250 P S T F
Caution
Set 2nd inertia ratio.
Youcansetuptheratiooftheloadinertiaagainsttherotor(ofthemotor)inertia.
Pr6.13=(loadinertia/rotorinertia)×100[%]
Iftheinertiaratioiscorrectlyset,thesetupunitofPr1.01andPr1.06becomes(Hz).When
theinertiaratioofPr0.04islargerthantheactual,thesetupunitofthevelocityloopgain
becomeslarger,andwhentheinertiaratioofPr0.04issmallerthantheactual,thesetupunit
ofthevelocityloopgainbecomessmaller.
Pr6.14
Emergency stop time at alarm
Range Unit Default
Related
control mode
0 to 1000 1 ms 200 P S T F
Setupthetimeallowedtocompleteemergencystopinanalarmcondition.Exceedingthis
time puts the system in alarm state.
Whensetupvalueis0,immediatestopisdisabledandtheimmediatealarmstopisenabled.
Pr6.15
2nd over-speed level setup
Range Unit Default
Related
control mode
0 to 20000 r/min 0 P S T F
Whenthemotorspeedexceedsthissetuptime,Err26.12ndover-speedprotectionwillbe
activated.
Theover-speedlevelbecomes1.2timesofthemotormax.speedbysettingupthisto0.
Pr6.16
For manufacturer's use
Range Unit Default
Related
control mode
—
— 0
Fixedto0.
Pr6.17
*
Frontpanelparameterwritingselection
Range Unit Default
Related
control mode
0 to 1 — 0 P S T F
SpecifytheEEPROMwritingprocedurewhenparameteriseditedformthefrontpanel.
Setup value Writing
[0] DonotwritetoEEPROMatthesametime
1 Write to EEPROM at the same time
Pr6.18
*
Power-upwaittime
Range Unit Default
Related
control mode
0 to 100 0.1s 0 P S T F
Setupthestandardinitializationtime(1.5s+
α
)afterpower-up.
Forexample,whensetupvalueis10,then1.5s+(10×0.1s)=approx.2.5s.
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