V-109
C
ONTROL
S
YSTEMS
Example
Suppose capacity values accumulated at 24:00 during one whole day is as follows.
360kWh consumed
(outdoor + indoor)
Strong cooling Week cooling Fan mode Stop
AB C D
Main capacity =105
Fan capacity = 20
Stand-by capacity = 5
Sum = 130
Main capacity = 60
Fan capacity = 20
Stand-by capacity = 5
Sum = 85
Main capacity = 0
Fan capacity = 20
Stand-by capacity = 5
Sum = 25
Main capacity = 0
Fan capacity = 0
Stand-by capacity = 5
Sum = 5
Pd of Indoor unit A = x Total kWh = = 192.020 kWh
Indoor unit capacity
Total capacity
Pd of Indoor unit B = = 124.900 kWh
85 x 360
130 + 85 + 25 + 5
Pd of Indoor unit C = = 36.735 kWh
25 x 360
130 + 85 + 25 + 5
Pd of Indoor unit D = = 7.347 kWh
5 x 360
130 + 85 + 25 + 5
130 x 360
130 + 85 + 25 + 5
05-3_control systems(082~141) 3/6/08 14:04 Page 109
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