EasyManua.ls Logo

Agilent Technologies 34420A - Accuracy Specifications

Agilent Technologies 34420A
294 pages
To Next Page IconTo Next Page
To Next Page IconTo Next Page
To Previous Page IconTo Previous Page
To Previous Page IconTo Previous Page
Loading...
Difference Error
Example
This example demonstrates how to compute the total measurement error
when using the Difference Function. Assume a difference measurement
is made with the following conditions:
Channel 1, 1 V input on the 1 Volt range
Channel 2, 1.2 V input on the 10 Volt range
To compute the total measurement error using the 90-day accuracy
specifications for the error:
Channel 1 (% of reading + % of range) + Channel 2 (% of reading + % of range).
Channel 1 Reading Error = 0.0025% 1 V
= 25 µV
Channel 1 Range Error = 0.0004% 1 V
= 4 µV
Channel 2 Reading Error = 0.0020% 1.2 V = 24
µV
Channel 2 Range Error = 0.0004% 10 V = 40 µV
Total Error = 25 µV
+ 4 µV + 24 µV + 40 µV = 93 µV
Difference = 1 V
1.2 V = 0.2 V ± 93 µV
For difference measurements, if both channel 1 and channel 2 are using
the same range, the % of reading error can be applied directly to to the
voltage difference. In the example, if both channels are using
the 1 V range, the total reading error can be computed as:
Reading Error = 0.0025% ( 1.2 V 1 V ) = 5 µV
Channel 1 Range Error = 0.0004% 1 V = 4 µV
Channel 2 Range Error = 0.0004% 1 V = 4 µV
Total Error = 5 µV + 4 µV + 4 µV =
13 µV
Difference = 1 V 1.2 V = 0.2 V ± 13
µV
Using NULL on each input channel will reduce the % of range error in
the measurement to the noise level of the meter.
8
Chapter 8
To Calculate Total Measurement Error
283

Table of Contents

Related product manuals