5-76
Application Manual CDA3000
5  Software functions
Calculation of effective inverter capacity utilization
Note: The following condition must be met for safe operation:
The following condition must additionally be met:
with
0.37 kW to 15 kW: [1.8 - 1]
.
30 s < 67.2 As
22 kW to 90 kW: [1.5 - 1]
.
60 s < 75 As
Figure 5.30 Effective inverter capacity utilization
TCycleduration
i
x
Current in cycle segment x in [A]
t
x
Time for cycle segment x in [s]
I
eff
Effective inverter current
I
eff
I
Ninverter–
<
0
v [m/s]
i[A]
i
1
i
2
i
3
i
4
i
5
t
1
t
2
t
3
t
4
t
5
T
I
eff
i
1
2
t
1
i
2
2
t
2
i
3
2
t
3
i
4
2
t
4
i
5
2
t
5
⋅+⋅+⋅+⋅+⋅
T
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