GE KVGC 202 - Page 58

K
VCG202/EN M/H11
Technical
Manual
KVGC202
Figure 27:
2R
L = 2RICT2 +
2(R
ICT2 + RL')
100
Therefore:
R
L = RICT2 +
(R
ICT2 + RL')
100
KVGC202 burden for LDC = 0.007Ω at In
Therefore:
RLDC = 0.007Ω
And
X =
R
L
RLDC
<0.0526
Therefore:
R
ICT1 +
(R
ICT2 + RL')
100
<0.0526
or RLDC must be increased to RLDC' via a series resistor so that:
R
LDC' > 19




RICT1 +
(R
ICT2 + RL')
100
e.g.
R
ICT1
= 0.02
R
ICT2
= 0.3
R
L
' = 0.2
This gives:
R
LDC' > 19




0.02 +
(0.03 + 0.2)
100
> 0.475
R
LDC
' = R
LDC
+ R
S
Therefore:
Rs > 0.475 – 0.007
> 0.468
Choose a value of 0.5Ω.
Required continuous current capability
2In = 10A