which results in a drop height ESTIMATE of
250 kg: h = (Pmax/k)PP
2
PP
= (11,000/ 935)PP
2
PP
= 138 mm (/25.4 = 5-1/2”)
350 kg: h = (Pmax/k)PP
2
PP
= (11,000/1,350)PP
2
PP
= 66 mm (/25.4 = 2-5/8”)
At system delivery, the drop heights will normally have been factory pre-adjusted to:
h1 = 50 mm, h2 = 100 mm, h3 = 200 mm and h4 = 390 mm
(h1 = 2”, h2 = 4”, h3 = 8” and h4 = 15-1/4”)
SO, IF you choose the 250 kg (550 lb.) weight, you can move stop no. 2 downwards from it’s
initial h2 = 100 mm (4”) to the desired 138 mm (5-1/2”).
OR, IF you choose the 350 kg (770 kg) weight, you can move stop no.1 downwards from it’s
initial h1 = 50 mm to the desired 66 mm (2-5/8”), BUT PLEASE NOTE that you then in
addition will have to move stop no. 2 downwards so much that the minimum distance of 50
mm (2”) between adjacent stops is achieved.
NOTE that all the above, calculated figures are theoretical and therefore only
APPROXIMATE, as the load is rather dependent on the stiffness of the pavement.
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Example 2 (UUHWDUU ONLY!):
If you want an approx. peak load of e.g. 18,000 lbf., then it can be seen from Table 4 that
the 340 kg (755 lb.) weight setup
can be used, and then Table 3 gives:
k = 1,700 lbf
which results in a drop height ESTIMATE of
h = (Pmax/k)PP
2
PP
= (18,000/ 1700)PP
2
PP
= 112 mm (/25.4 =4.4 ”)
At system delivery, the drop heights will normally have been factory pre-adjusted to:
h1 = 50 mm, h2 = 100 mm, h3 = 200 mm and h4 = 390 mm
(h1 = 2”, h2 = 4”, h3 = 8” and h4 = 15-1/4”)
SO, in the above example it would be convenient to readjust h2 to 112 mm (4.4”). (This gives
a distance to h3 of 88 mm (3.5”), which is greater than 50 mm (2”) as prescribed).
NOTE that all the above, calculated figures are theoretical and therefore only
APPROXIMATE, as the load is rather dependent on the stiffness of the pavement.
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