HP 48GII - Simple Moment (1, 5); Simple Shear (1, 6)

5-6 Equation Reference
Example:
Given: L=20_ft, E=29000000_psi, I=40_in^4, a=10_ft, P=674.427_lbf, c=17_ft, M=3687.81_ft
∗ lbf,
w=102.783_lbf/ft, x=9_ft.
Solution:
Θ = -0.0876_°.
Simple Moment (1, 5)
Equation:
Mx
PLa–()x⋅⋅
L
--------------------------------
Mx⋅
L
------------
wx⋅
2
-----------
+Lx–()⋅+=
Example:
Given: L=20_ft, a=10_ft, P=674.427_lbf, c=17_ft, M=3687.81_ft
∗ lbf, w=102.783_lbf / ft, x=9_ft.
Solution: Mx=9782.1945_ft
∗ lbf
Simple Shear (1, 6)
Equation:
V
PLa–()⋅
L
-------------------------
M
L
-----
w
2
----
+L2–x⋅()⋅+=
Example:
Given: L=20_ft, a=10_ft, P=674.427_lbf, M=3687.81_ft
∗ lbf, w=102.783_lbf/ft, x=9_ft.
Solution: V=624.387_lbf.