HP 48GII

5-54 Equation Reference
Equations:
I D G 0 V D S
2
3
- - -
2
ε
s i
ε
0
⋅ ⋅
q
N
D a
2
⋅ ⋅
- - - - - - - - - - - - - - - - - - - - - - - - - -
⋅
⎝
⎠
⎜
⎛
⎞
–
⎝
⎜
⎛
⋅
=
V b i
k T
⋅
q
- - - - - - - - - - -
L
N
N
D
n i
- - - - - - - - -
⎝
⎠
⎛
⎞
⋅
=
V b i V G S
–
V D S +
( )
3
2
- - -
V b i V G S
–
( )
3
2
- - -
–
⎝
⎠
⎜
⎛
⎞
V D s a t
q
N
D a
2
⋅ ⋅
2
ε
s i
ε
0
⋅ ⋅
- - - - - - - - - - - - - - - - - - - - - - - - - -
V b i V G S
–
( )
–
=
x d m a x
2
ε
s i
ε
0
⋅ ⋅
q
N
D
⋅
- - - - - - - - - - - - - - - - - - - - - - - - - -
V b i V G S
–
V DS+
( )⋅
=
g m G 0 1
2
ε
s i
ε
0
⋅ ⋅
q
N
D a
2
⋅ ⋅
- - - - - - - - - - - - - - - - -- - - - - - - - -
V b i V G S
–
( )⋅
–
⎝
⎠
⎜
⎛
⎞
⋅
=
V t Vbi
q
N
D a
2
⋅ ⋅
2
ε
si
ε
0
⋅ ⋅
--------------------------
–
=
G
0 q
N
D
µ
n
a W
⋅
L
- - - - - - - - - - - -
⎝
⎠
⎛
⎞
⋅ ⋅ ⋅
=
Example:
Given: ND=1E16_1/cm^3, W=6_
µ , a=1_ µ , L=2_ µ , µ n= 1248_cm^2/ (V ∗ s), VGS= -4_V, VDS=4_V,
T=26.85°C.
Solution: Vbi=0.3493_V, xdmax=1.0479_
µ, G0=5.9986E–4_S, ID=0.2268_mA, VDsat=3.2537_V,
Vt= -7.2537_V, gm=0.1462_mA/V.
Stress Analysis (14)
Variable
Description
δ
Elongation
∈
Normal strain
γ
Shear strain
φ
Angle of twist
σ
Normal stress
σ 1
Maximum principal normal stress