HP 48GII - Solenoid Inductance (2, 20); Toroid Inductance (2, 21)

Equation Reference 5-17
Example:
Given:
∈ r=1, ro=1_cm, ri=.999_cm, L=10_cm.
Solution: C=0.0056_µF.
Solenoid Inductance (2, 20)
Equation:
Example:
Given: µr=2.5, n=40_1/cm, A= .2_cm^2, h=3_cm.
Solution: L=0.0302_mH.
Toroid Inductance (2, 21)
Equation:
Example:
Given: µr=1, N=5000, h=2_cm, ri= .2_cm, ro=4_cm.
Solution: L=69.3147_mH.
L
µ
0
µ
r n
2
A h
⋅ ⋅ ⋅ ⋅
=
L
µ
0
µ
r
N
2
h
⋅ ⋅ ⋅
2
π ⋅
- - - - - - - - - - - - -- - - - - - - - - - - - - - - - - - - - - - -
L
N
ro
ri
-----
⎝
⎠
⎛
⎞
⋅
=