HP 48GII

5-42 Equation Reference
Conical Pendulum (10, 3)
Equations:
Example:
Given: L=25_cm, h=20_cm.
Solution:
θ =36.899_°, T= 0.8973_s, ω =7.0024 r/s, f=1.1145_Hz.
Torsional Pendulum (10, 4)
Equations:
Example:
Given: G=1000_kPa, J=17_mm^4, L=26_cm, I=50_kg
∗ m^2.
Solution:
ω =1.1435E°–3_r/s, f=1.8200E–4_Hz, T=5494.4862_s.
Simple Harmonic (10, 5)
Equations:
ω
g
h
- - - =
h L C O S
θ
( ) ⋅
=
T
2
π⋅
ω
----------
=
ω
2
π
f
⋅ ⋅
=
w
G J
⋅
L I
⋅
- - - - - - - - - - - =
T
2
π ⋅
ω
- - - - - - - - - -
=
ω
2
π
f
⋅ ⋅
=
x x m C O S
ω
t
⋅
φ
+
( ) ⋅
=
v
ω
–
xm SI
N
ω
t
⋅
φ
+
( )⋅ ⋅
=
a
ω
2
–
x m C O S
ω
t
⋅
φ
+
( ) ⋅ ⋅
=
ω
2
π
f
⋅ ⋅
=