HP 48GII - Angular Motion (8, 4); Circular Motion (8, 5); Terminal Velocity (8, 6); Escape Velocity (8, 7)

5-36 Equation Reference
Angular Motion (8, 4)
Equations:
Example:
Given:
Θ 0=0_°, ω 0=0_r/min, α =1.5_r/min^2, t=30_s.
Solution:
Θ =10.7430_°, ω = 0.7500_r/min.
Circular Motion (8, 5)
Equations:
Example:
Given: r=25_in, v=2500_ft/s
Solution:
ω=72000_r/min, ar=3000000_ft/s^2, N=11459.1559_rpm.
Terminal Velocity (8, 6)
Equation:
Example:
Given: Cd=0.15,
ρ =0.025lb/ft^3, A=100000_in^2, m=1250_lb.
Solution: v=1757.4709_ft/s.
Escape Velocity (8, 7)
Equation:
v
2GM⋅⋅
R
---------------------=
Example:
Given: M=1.5E23_lb, R=5000_mi.
Solution: v=3485.1106_ft/s.
θ θ
0
ω
0 + t
⋅
1
2
- - -
+
α
t
2
⋅ ⋅
=
θ θ
0
ω
+ t
⋅
1
2
---
+
α
t
2
⋅ ⋅
=
θ θ
0
1
2
- - -
+
ω
0
ω
+
( )
t
⋅ ⋅
=
ω ω
0
α
+ t
⋅
=
ω
v
r
- - -
=
ar
v
2
r
- - - - -
=
ω
2
π
N
⋅ ⋅
=
v
2 m g
⋅ ⋅
C d
ρ
⋅
A
⋅
- - - - - - - - - - - - - - - - - - - - - - - - =