6 Assi
nin
Parameters to the Control and the PLC Pro
ram
6
03.96
6.9 Axes and spindles
6-143
 Siemens AG 2000 All Rights Reserved
SINUMERIK 840D Installation and Start-Up Guide (IAD) – 04.00 Edition
Note
These MD are not required to match the encoder, but they must be entered
correctly for setpoint calculation. The load revolutions are entered in
MD 31050: DRIVE_AX_RATIO_DENOM and the motor revolutions in
MD 31060: DRIVE_AX_RATIO_NUMERA.
Spindle with signal generator (500 pulses) mounted directly on spindle. Internal
multiple = 2048. Internal calculation resolution = 1000 increments per degree.
MD 31020 * 2048
360 degrees
Internal resolution =
MD 31070
MD 31080
**
1000
500 * 2048 *1
360 * 1 * 1000
Internal resolution =
0.3515
The encoder increment corresponds to 0.3515 internal increments. An encoder
increment corresponds to 0.003515 degrees (highest possible positioning
resolution).
Spindle with rotary encoder on motor (2048 pulses), internal multiple = 2048, 2
gear stages:
Gear stage 1: Motor/spindle = 2.5/1
Gear stage 2: Motor/spindle = 1/1
Gear stage 1
MD 31020 * 2048
360 degrees
MD 31070
MD 31080
**
1000 incr/degr.
*
MD 31060
MD 31050
Internal
resolution
=
2048 * 2048 pulses
360 degrees
1
**
1000 pulses/degree
1
1
*
2,5
= 0.034332
Internal
resolution
=
One encoder increment corresponds to 0.034332 internal increments. An
encoder increment corresponds to 0.000034332 degrees (highest possible
positioning resolution).
Gear stage 2
MD 31020 * 2048
360 degrees
MD 31070
MD 31080
**
1000 incr/degr.
*
MD 31060
MD 31050
Internal
resolution
=
2048 * 2048 pulses
360 degrees
1
**
1000 pulses/degree
1
1
*
1
= 0.08583
Internal
resolution
=
One encoder increment corresponds to 0.08583 internal increments. One
encoder increment corresponds to 0.00008583 degrees (highest possible
positioning resolution).
Example A of
encoder matching
Example B of
encoder matching
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