164
Ignore the 1 in bit14,
bit12, bit10, bit8
unchanged.
When n = 16, if the of encoding instruction is a bit element, its point is 2 ^ 16 = 65536.
n = 3, the encoded object has 2
3
= 8 bits, which are M17 ~ M10, and the encoding results are
stored in the lower three bits of D10, which are bit2 ~ bit0.
M12 and M16 are both 1. Ignoring M16, M12 is coded, bit2-bit0 represent 2, while bit1 is 1.
< if is word device> n≤4
If multiple bits in the source address is 1, the high bit side is ignored, and if the source
address is 0, the instruction will not be executed.
When the driver input is OFF, the instruction is not executed and the coding output is
unchanged.
When n ≤3, the high 8 bits in D0 are neglected.
The encoding object has 2
3
= 8 bits, that is, bit7 ~ bit0 in D0. The encoding result is stored in
the lower 3 bits in D1, that is, bit2 ~ bit0.
When bit7 and bit4 in D0 are both 1, bit7 is ignored and bit4 is coded. Bit 2 is 1 when bit2-
bit0 is expressed as 4.
< is word soft component > n≤4
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