Revision 2016/03, 6ELE, V1.14
4-35
Therefore the distance travelled by the motor after the stop command is given = number of rounds x circumference
= 175x 2πr. That means the turbtable went back to the top after 175 rounds.
Example 02
Suppose that turntable is rotating at 1.5Hz, the Pr01.22 =10Hz [Simple Positioning Stop Frequency 2], and Pr01.30
=10 sec [Delay Time of Simple Positioning Stop 2], then the deceleration time will be 40 sec for decreasing from
60Hz to 0Hz.
The delay time to stop of 1.5Hz is 1.5sce, the deceleration time is 1 sec for decreasing from 1.5Hz to 0 Hz.
When stop command is given, Simple Positioning Stop will be activate, its rotation speed is
n = 120x1.5/4
（
round/ minute
）
= 1.5/2
（
round / second
）
Number of rounds of motor turntable = (1.5/2 x (1.5 + 2.5)) / 2 = 1.5(rounds)
Therefore the distance travelled by the motor after the stop command is given = number of rounds x circumference
= 1.5x 2πr. That means the turbtable stopped after 1.5 rounds.
To Next Page
Loading...
