Vigor VS Series - Page 329

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Assume the content value of the 32-bit instruction's D10=13, D11=8 and (D21, D20)=-123450, the instruction will
be executed as follows:
–123450
D10
D11
13
8
S1
S2
( D21, D20)
0 0 0
1
2
3
4
5
0
–
Negative sign
Empty, inserts two space codes
123450
Insert the 0s and a decimal point
For example, the =3 and =123, that will be regarded as an operating error. Since, the = 123 is a 3
digits number, but to convert that will need a digit for the positive or negative sign in the front. So, the should
greater than or equal to 4.
S1
DSTR D10 D20 D0
X0
S1
S2
D
S1
S2 S2
Length of the converted string
Number of digits after
the decimal point