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9.3 Photometry Assay Concentration Calculation
This calculation is exemplified below on ALB.
Assume that standard solution 1 (reagent blank) and standard solution 2 have concentrations of
0.0 g/dL and 5.3 g/dL, respectively.
Calculation of S1ABS (absorbance of standard solution 1 × 10
4
)
S1ABS =
448
+
445
2
=
446.5 447
"447" is indicated on the monitor menu 2 screen.
Calculation of K factor
K =
C C
A B
2 1
2
−
−
C
2
: Concentration of standard solution 2
C
1
: Concentration of standard solution 1
A
2
: Printed absorbance of standard solution 2 × 10
-4
B : Printed absorbance of standard solution 1 × 10
-4
In the calculation of K value, each concentration value is rewritten into the integral part and
exponential part, and calculation is carried out while ignoring the fractional digits (and the
exponential part). The number of fractional digits is counted with reference to the concentration
value of standard solution 1. Therefore, 0.0 is rewritten into 0 × 10
-1
, and 5.3 into 53 × 10
-1
, and
values 0 and 53 are used for calculation.
The value 202 obtained by calculation is indicated on the monitor menu 2 screen.
K =
(
)
53 0
3050 3097
2
448 445
2
10
53
3074 447 10
202
4
4
−
+
−
+
×
=
− ×
=
−
−
Rounding off
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