Omron SYSMAC CV Series - Find Minimum: Min(166)

(165)
MAX D03000 0200 D00500
0000
00
320
Example When CIO 000000 is ON in the following example, MAX(165) outputs to D00500
the maximum value within the 10-word range from CIO 0200 to CIO 0209. Be-
cause bit 14 of C is ON, the lower address of the two addresses within the range
that contain the maximum value is output to IR0.
Address Instruction Operands
00000 LD 000000
00001 MAX(165)
D03000
0200
D00500
D03000 4010
0200 3F2A $00C8
0201 51C3 $00C9
0202 E02A $00CA
0203 7C9F $00CB
0204 2A20 $00CC
0205 A827 $00CD
0206 2A20 $00CE
0207 E02A $00DF
0208 C755 $00D0
0209 94DC $00D1
D00500 E02A
IR0 00CA
10 words
5-23-2 FIND MINIMUM: MIN(166)
Variations
j MIN(166)a
(166)
MIN C R
1
D
R
1
: 1
st
word in range CIO, G, A, T, C, DM
D: Destination word CIO, G, A, DM, DR, IR
C: Control word CIO, G, A, #, DM, DR, IR
Operand Data AreasLadder Symbol
When the execution condition is OFF, MIN(166) is not executed. When the ex-
ecution condition is ON, MIN(166) searches the range of memory from R
1
to
R
1
+N–1 for the address that contains the minimum value, outputs that value to
the destination word (D) and, if bit 14 of C is ON, outputs the memory address of
the word containing the minimum value to IR0.
If bit 14 of C is ON and more than one address contains the same minimum val-
ue, the lowest of the addresses will be output to IR0.
The number of words within the range (N) is contained in the 3 rightmost digits of
C, which must be BCD between 001 and 999.
Description
Special Math Instructions Section 5-23