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6 BASIC INSTRUCTIONS
6.2 Arithmetic Operation Instructions
D-(P)(_U) [using three operands]
These instructions subtract the 32-bit binary data in the device specified by (s1) and the 32-bit binary data in the device
specified by (s2), and store the result in the device specified by (d).
■Descriptions, ranges, and data types
■Applicable devices
• These instructions subtract the 32-bit binary data in the device specified by (s1) and the 32-bit binary data in the device
specified by (s2), and store the subtraction result in the device specified by (d).
• When underflow or overflow occurs in the operation result, the following processing is executed. In this case, the carry flag
(SM700, SM8022) does not turn ON.
There is no operation error.
Ladder diagram Structured text
ENO:=DMINUS(EN,s1,s2,d);
ENO:=DMINUSP(EN,s1,s2,d);
ENO:=DMINUS_U(EN,s1,s2,d);
ENO:=DMINUSP_U(EN,s1,s2,d);
Operand Description Range Data type Data type (label)
(s1) D-(P) Minuend data or the head device where the
data from which another is to be subtracted is
stored
-2147483648 to +2147483647 32-bit signed binary ANY32_S
D-(P)_U 0 to 4294967295 32-bit unsigned binary ANY32_U
(s2) D-(P) Subtrahend data or the head device where the
data to be subtracted from another is stored
-2147483648 to +2147483647 32-bit signed binary ANY32_S
D-(P)_U 0 to 4294967295 32-bit unsigned binary ANY32_U
(d) D-(P) Head device for storing the operation result 32-bit signed binary ANY32_S
D-(P)_U 32-bit unsigned binary ANY32_U
Operand Bit Word Double word Indirect
specification
Constant Others
X, Y, M, L,
SM, F, B, SB
U\G T, ST,
C, LC
T, ST, C, D,
W, SD, SW, R
U\G Z LC LZ K, H E $
(s1)
(s2)
(d)
b0
567890 (BIN)
(s1)
123456 (BIN) 444434 (BIN)
-
··· ···
(s1)+1
(s2)
(s2)+1
(d)
(d)+1
b31 b16 b15
b0
··· ···
b31 b16 b15
b0
··· ···
b31 b16 b15
- →
-
→
- →
K0 K4294967295 K1
(00000000H) (FFFFFFFFH) (00000001H)
- →
K2147483647 K-2 K-2147483647
K0 K1 K4294967295
K-2147483648 K2 K2147483646
(00000000H) (00000001H) (FFFFFFFFH)
(80000000H) (00000002H) (7FFFFFFEH)
(FFFFFFFEH) (80000001H)(7FFFFFFFH)
In case of D-(P)
Because the highest bit is 1, the value is negative.
In case of D-(P)(_U)
Because the highest bit is 0, the value is positive.
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