Cabinet Configuration and EMC Booksize
7.7 Cooling
Equipment Manuel for Booksize Power Modules
7-44 Manual, (GH2), Edition 06.2005, 6SL3097-2AC00-0BP2
7.7.4 Dimensioning Climate Control Equipment
Cabinet manufacturers provide calculation programs for selecting climate control equipment.
It is always necessary to know the power loss of the components and equipment installed in
the cabinet.
The physical relationship is shown in the following example.
Figure 7-19 Example of dimensioning climate control equipment
q = thermal power that has to be dissipated through a cooling unit [W / K]
Q = power loss [W]
∆T = temperature difference between the room and cabinet interior [K]
k = thermal resistance value, e.g. sheet-steel, painted 5.5 [W / (m
2
* K)]
A = free-standing cabinet surface area [m
2
]
Table 7-19 Example of a power loss calculation
Component Number Power loss [W] Total power loss [W]
CU320 1 20 20
Line Filters 1 250 250
Line reactor 1 250 250
Active line module 36 kW 1 580 580
Motor module 18 A 2 165 330
Motor module 30 A 3 290 870
Encoders 5 10 50
SITOP 20 1 53 53
Line Contactor 1 12 12
Total: 2415
Assumption:
Free-standing cabinet surface area A = 5 m
2
Temperature difference between the room and cabinet interior ∆T = 10 K
q = (2415 [W] / 10 [Κ]) - 5.5 [W / (m
2
* K)] * 5 [m
2
] = 214 [W/K]