Detailed Description
2.4 Tool radius compensation 2D (TRC)
Basic logic functions: Tool Offset (W1)
72 Function Manual, 11/2006, 6FC5397-0BP10-2BA0
Part program:
$TC_DP1[1,1]=120
;Tool definition T1/D1
$TC_DP6[1,1]=10
; Radius
N10 G0 X0 Y0 Z30
N20 G247 G341 G42 NORM D1 T1 Z0 FAD=1000 F=2000 DISCL=5 DISR=10
N30 X40
N40 X100
N50 Y-30
...
Example 2
The following conditions must be true for approach:
• Smooth approach is activated in block N20
• Approach movement performed with quadrant (G247)
• Approach direction not programmed, G140 is valid, i.e., because TRC is active (G41), the
contour is approached from the left
• Contour offset OFFN=5 (N10)
• Current tool radius=10, and so the effective compensation radius for TRC=15; the radius
of the SAR contour is thus equal to 25, with the result that the radius of the tool center
path is equal to DISR=10
• The end point of the circle is obtained from N30, since only the Z position is programmed
in N20
• Infeed movement
– From Z20 to Z7 (DISCL=AC(7)) with rapid traverse
– Then on to Z0 with FAD=200
– Approach circle in X-Y-plane and following blocks with F1500
(In order that this velocity becomes effective in the following blocks, the active G-code
G0 in N30 must be overwritten with G1. Otherwise, the contour would continue to be
machined with G0.)
The following conditions must be true for retraction:
• Smooth retraction is activated in block N60
• Retraction movement performed with quadrant (G248) and helix (G340)
• FAD not programmed, since irrelevant for G340
• Z=2 in the start point; Z=8 in the end point, since DISCL=6
•
When DISR=5, the radius of SAR contour=20; that of the tool center point path=5
• After the circle block, the retraction movement leads from Z8 to Z20 and the movement is
parallel to the XY plane up to the end point at X70 Y0.
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