Hioki IM3533 - Page 356

14.2 Measurement Range and Accuracy
348
• Capacitance (Cs=160 nF) basic accuracy
(For example) Measurement conditions:measurement frequency=1 kHz, measurement speed=SLOW2
Accuracy table (p.343)
range
1.0000 kHz to
10.000 kHz
100 k
10 k
A= 0.05 B= 0.02
A= 0.03 B= 0.02
1 k
1. Measure the sample’s Z and values using auto-ranging.
2. Assume that the measured Z and
 values are as follows:
Z = 1.0144 k,
 = -78.69°
Because Z is 1.0144 , the 10 k measurement range will be used.
3. Obtain the Z coefficients A and B from the accuracy table (p.343) and then calculate the
basic accuracy of Z. In the 1 kHz/10 k range, the accuracy table (p.343) yields the values
A = 0.05 and B = 0.02.
Using the basic accuracy formula (p.342) for 1 k or more ranges,
Z

4. Similarly, calculate the basic accuracy of
.
The accuracy table (p.343) yields the values A = 0.03 and B = 0.002.
Using the basic accuracy formula (p.342) for 1 k or more ranges,
Z accuracy=±
accuracy=±
5. Calculate the range within which Z and
 values can be acquired from the basic accuracy.
Zmin = 1.0144 k × (1 - ) 1.0139 k
Zmax = 1.0144 k × (1 + ) 1.0149 k
min = -78.69 - 0.03 = -78.72°
max = -78.69 + 0.03 = -78.66°
6. Calculate the range within which Z and
 values can be acquired from the basic accuracy.
(For more information about the Cs calculation formula, see "Appendix1 Measurement Parameters
and Calculation Formula"(p. A1).)
100
0.05
100
0.05
Csmin = -
Csmax = -
 = 2
××f f = frequency [Hz]
7. Consequently, the Cs basic accuracy is ±0.0625%.
10×1.0144×10
3
10×10
3
- 1
0.05+ 0.02 ×
±0.05%
10×1.0144×10
3
10×10
3
- 1
0.03+ 0.02 ×
1

×Zmax×sinmin
159.90nF ...-0.0625%
1

×Zmin×sinmax
160.10nF ...0.0625%
±0.03