RL78/G1H CHAPTER 31 ELECTRICAL SPECIFICATIONS
R01UH0575EJ0120 Rev. 1.20 Page 881 of 920
Dec 22, 2016
Note 1. The smaller maximum transfer rate derived by using fMCK/6 or the following expression is the valid maximum transfer
rate.
Expression for calculating the transfer rate when 2.7 V
≤ VDD < 3.6 V and 2.3 V ≤ Vb ≤ 2.7 V
Note 2. This value as an example is calculated when the conditions described in the “Conditions” column are met.
Refer to
Note 1 above to calculate the maximum transfer rate under conditions of the customer.
Note 3. Use it with VDD ≥ Vb.
Note 4. The smaller maximum transfer rate derived by using fMCK/6 or the following expression is the valid maximum transfer
rate.
Expression for calculating the transfer rate when 1.8 V
≤ VDD < 3.3 V and 1.8 V ≤ Vb ≤ 2.0 V
Note 5. This value as an example is calculated when the conditions described in the “Conditions” column are met.
Refer to
Note 4 above to calculate the maximum transfer rate under conditions of the customer.
(Caution and Remarks are listed on the next page.)
(5) Communication at different potential (1.8 V, 2.5 V, 3 V) (UART mode)
(T
A = ‒40 to +85 °C, 1.8 V ≤ VDD ≤ 3.6 V, VSS = 0 V) (2/2)
Parameter Symbol Conditions HS (high-speed main)
mode
LS (low-speed main)
mode
Unit
MIN. MAX. MIN. MAX.
Transfer rate transmission 2.7 V
≤ VDD < 3.6 V,
2.3 V
≤ Vb ≤ 2.7 V
Note 1 Note 1 bps
Theoretical value of the
maximum transfer rate
Cb = 50 pF, Rb = 2.7 kΩ,
Vb = 2.3 V
1.2
Note 2
1.2
Note 2
Mbps
1.8 V
≤ VDD < 3.3 V,
1.6 V
≤ Vb ≤ 2.0 V
Notes 3, 4 Notes 3, 4
bps
Theoretical value of the
maximum transfer rate
Cb = 50 pF, Rb = 5.5 kΩ,
Vb = 1.6 V
0.43
Note 5
0.43
Note 5
Mbps
Maximum transfer rate =
1
[bps]
Baud rate error (theoretical value) =
1
Transfer rate
× 2
-
{-C
b × Rb × In (1 - )} × 3
2.0
V
b
{-Cb × Rb × In (1 - )}
2.0
V
b
( ) × Number of transferred bits
1
Transfer rate
× 100 [%]
* This value is the theoretical value of the relative difference between the transmission and reception sides .
Maximum transfer rate =
1
[bps]
Baud rate error (theoretical value) =
1
Transfer rate
× 2
-
{-C
b × Rb × In (1 - )} × 3
1.5
V
b
{-Cb × Rb × In (1 - )}
1.5
V
b
( ) × Number of transferred bits
1
Transfer rate
× 100 [%]
* This value is the theoretical value of the relative difference between the transmission and reception sides .
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