Juniper MX2020 - Page 210

Figure 70: AC PDM Three-Phase Delta Input Power
g007085
AC PS_0
2800W
input
AC PS_3
2800W
input
AC PS_1
2800W
input
AC PS_4
2800W
input
AC PS_2
2800W
input
AC PS_5
2800W
input
A1
B1
AC PS_8
2800W
input
A2
B2
C2
AC PS_6
2800W
input
AC PS_7
2800W
input
C1
AC PSM VIN=200-240 single phase:
a. Two AC PSMs are connected in parallel between two lines.
b. Nominal value of input current for one AC PSM is 2800 W/200 V=14 A.
c. Nominal input current for two AC PSMs is 2*14 A=28 A.
d. Nominal value of line current is 28 A*√3=48.5 A.
e. So, input #1 rated current is 50 A.
f. Only one AC PSM is connected between two lines.
g. Nominal value of input current for one AC PSM is 2800 W/200 V=14 A.
h. Nominal value of line current is 14 A*√3=24.5 A.
i. Current rating for input #2 is 25 A.
4. To calculate necessary input power for three-phase wye AC PDM, follow the procedure below (see
Figure 71 on page 189).
188