ABB 615 Series - Page 248

Cross-polarizing as polarizing quantity
Table 240: Equations for calculating angle difference for cross-polarizing method
Faulted
phases
Used
fault
current
Used
polarizing
voltage
Angle difference
A I
A
V
BC
ANGLE A V I
BC
A
RCA
o
_ ( ) - ( ) - = + ϕ ϕ ϕ 90
GUID-330CBC28-7CE9-431A-9EC2-8590092DDAFF-ANSI V1 EN
B
I
B
V
CA
ANGLE B V I
CA
B
RCA
o
_ ( ) - ( ) - = + ϕ ϕ ϕ 90
GUID-3D93A608-FA6D-4F3E-9264-19776122A8E1-ANSI V1 EN
C
I
C
V
AB
ANGLE C V I
AB
C
RCA
o
_ ( ) - ( ) - = + ϕ ϕ ϕ 90
GUID-03176C00-8F5C-4791-A92C-9DBC0BA47EBF-ANSI V1 EN
A - B
I
A
- I
B
V
BC
- V
CA
ANGLE A V V I I
BC CA
A B
RCA
o
_ ( - ) - ( - ) - = + ϕ ϕ ϕ 90
GUID-FA1C82F1-94F6-4669-8303-D465948F0611-ANSI V1 EN
B - C
I
B
- I
C
V
CA
- V
AB
ANGLE B V V I I
CA AB
B C
RCA
o
_ ( - ) - ( - ) - = + ϕ ϕ ϕ 90
GUID-6D5785FC-2D25-48F9-B5D6-BD4E12A440E8-ANSI V1 EN
C - A
I
C
- I
A
V
AB
- V
BC
ANGLE C V V I I
AB BC
C A
RCA
o
_ ( - ) - ( - ) - = + ϕ ϕ ϕ 90
GUID-B1524B24-5D74-4E0F-9432-7D19AC5A18C3-ANSI V1 EN
The angle difference between the polarizing quantity V
BC
and operating quantity I
A
is
marked as φ in an example of the phasors in a single-phase ground fault where the faulted
phase is phase A. The polarizing quantity is rotated with 90 degrees. The characteristic
angle is assumed to be ~ 0 degrees.
Section 4 1MAC059074-MB A
Protection functions
242 615 series ANSI
Technical Manual