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Parker Compax3 Fluid T40

Parker Compax3 Fluid T40
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Parker EME
Motion control
192-121102 N04 June 2008 287
Numerical Example:
Product: 314,871 long
14 products are to be transported per load revolution via a curve.
Gearbox: Motor/Load = 6949673 / 43890 => i = 158.3429...
1. Variant (with drift)
Load revolutions = (number of the products) * (length of a product) * (reciprocal of
the travel path per motor revolution slave axis) * (gearbox load / motor)
N2 43890 Load revolutions = 14 * 314.871mm *
Z2
*
6949673
43890 Z2 193475634,66 14 * 314,871mm *
6949673
=
N2
=
6949673
This factor can not be expressed exactly in Compax3; the max. entry allowed in the
Compax3 ServoManager:
1934756
69496
which causes drift.
2. Variant (without drift)
Slave clock distance = 1 product cycle
For this, the curve is created scaled to 1.
N2 43890 Load revolutions = 14 * 1mm *
Z2
*
6949673
43890 Z2 614460 14 * 1mm *
6949673
=
N2
=
6949673
This factor for the path per motor revolution can be expressed, no drift is
generated!

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